11m^2-34m+3=0

Solution for 11m^2-34m+3=0 equation:

11m^2-34m+3=0

a = 11; b = -34; c = +3;
Δ = b2-4ac
Δ = -342-4·11·3
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-32}{2*11}=\frac{2}{22}
=1/11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+32}{2*11}=\frac{66}{22}
=3
$